810=-490t^2+1260t

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Solution for 810=-490t^2+1260t equation: 



810=-490t^2+1260t

We move all terms to the left:

810-(-490t^2+1260t)=0

We get rid of parentheses

490t^2-1260t+810=0

a = 490; b = -1260; c = +810;
Δ = b2-4ac
Δ = -12602-4·490·810
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{1260}{980}=1+2/7$

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